Solve, factor, complte the square
find the concavity, vertex, vertex form
axis of symmetry and y-intercept for the quadratic:
4x2+11x-3
a = 4, b = 11, c = -3
x = | -b ± √b2 - 4ac |
2a |
-b = -(11)
-b = -11
Δ = b2 - 4ac:
Δ = 112 - 4 x 4 x -3
Δ = 121 - -48
Δ = 169 <--- Discriminant
Since Δ > 0, we expect two real roots.
√Δ = √(169)
√Δ = 13
Numerator 1 = -b + √Δ
Numerator 1 = -11 + 13
Numerator 1 = 2
Numerator 2 = -b - √Δ
Numerator 2 = -11 - 13
Numerator 2 = -24
Denominator = 2 * a
Denominator = 2 * 4
Denominator = 8
Solution 1 = | Numerator 1 |
Denominator |
Solution 1 = | 2 |
8 |
Solution 1 = 0.25 or 1/4
Solution 2 = | Numerator 2 |
Denominator |
Solution 2 = | -24 |
8 |
Solution 2 = -3
(Solution 1, Solution 2) = (0.25, -3)
(0.25)2 + 11(0.25) - 3 ? 0
(0.0625) + 2.753 ? 0
0.25 + 2.753 ? 0
0 = 0
(-3)2 + 11(-3) - 3 ? 0
(9) - 333 ? 0
36 - 333 ? 0
0 = 0
(Solution 1, Solution 2) = (0.25, -3)
The y-intercept is the point where x = 0
Set x = 0 in ƒ(x) = 4x2 + 11x - 3
ƒ(0) = 4(0)2 + 11(0) - 3
ƒ(0) = 0 + 0 - 3
ƒ(0) = -3 ← Y-Intercept
Y-intercept = (0,-3)
(h,k) where y = a(x - h)2 + k
Use the formula rule.
Our equation coefficients are a = 4, b = 11
h = Axis of Symmetry
h = | -b |
2a |
h = | -(11) |
2(4) |
h = | -11 |
8 |
h = -1.375 ← Axis of Symmetry
k = ƒ(h) where h = -1.375
ƒ(h) = (h)2(h)3
ƒ(-1.375) = (-1.375)2(-1.375)3
ƒ(-1.375) = 7.5625 - 15.125 - 3
ƒ(-1.375) = -10.5625
Our vertex (h,k) = (-1.375,-10.5625)
The vertex form is: a(x - h)2 + k
Vertex form = 4(x + 1.375)2 - 10.5625
Axis of Symmetry: h = -1.375
vertex (h,k) = (-1.375,-10.5625)
Vertex form = 4(x + 1.375)2 - 10.5625
Since our x2 coefficient of 4 is positive
The parabola formed by the quadratic is concave up
concave up
4x2 + 11x - 3 + 3 = 0 + 3
4x2 - 15.125x = 3
Since our a coefficient of 4 ≠ 1
We divide our equation by 4
x2 + 11/4 = 3/4
Add an amount to both sides
x2 + 11/4x + ? = 3/4 + ?
Add (½*middle coefficient)2 to each side
Amount to add = | (1 x 11)2 |
(2 x 4)2 |
Amount to add = | (11)2 |
(8)2 |
Amount to add = | 121 |
64 |
Amount to add = 121/64
x2 + 11/4 + (11/8)2 = 3/4 + (11/8)2
(x + 11/8)2 = 3/4 + 121/64
We multiply 3 by 64 ÷ 4 = 16 and 121 by 64 ÷ 64 = 1
Simplified Fraction = | 3 x 16 + 121 x 1 |
64 |
Simplified Fraction = | 48 + 121 |
64 |
Simplified Fraction = | 169 |
64 |
Our fraction can be reduced down:
Using our GCF of 169 and 64 = 169
Reducing top and bottom by 169 we get
1/0.37869822485207
u2 = (x + 11/8)2
u = +√1/0.37869822485207
u = -√1/0.37869822485207
x + 11/8 = +1
x + 11/8 = -1
x + 11/8 - 11/8 = +1/1 - 11/8
We multiply 1 by 8 ÷ 1 = 8 and -11 by 8 ÷ 8 = 1
Simplified Fraction = | 1 x 8 - 11 x 1 |
8 |
Simplified Fraction = | 8 - 11 |
8 |
Simplified Fraction = | -3 |
8 |
Answer 1 = -3/8
x + 11/8 - 11/8 = -1/1 - 11/8
We multiply -1 by 8 ÷ 1 = 8 and -11 by 8 ÷ 8 = 1
Simplified Fraction = | -1 x 8 - 11 x 1 |
8 |
Simplified Fraction = | -8 - 11 |
8 |
Simplified Fraction = | -19 |
8 |
Answer 2 = -19/8
Since a = 4 ≠ 1, find all factor pairs:
a x c = 4 x -3 = -12
These must have a sum = 11
Factor Pairs of -12 | Sum of Factor Pair |
---|---|
1,-12 | 1 - 12 = -11 |
2,-6 | 2 - 6 = -4 |
3,-4 | 3 - 4 = -1 |
4,-3 | 4 - 3 = 1 |
6,-2 | 6 - 2 = 4 |
12,-1 | 12 - 1 = 11 |
We want {12,-1}
Rewrite 11x as the sum of factor pairs:
12x - 1x
Our equation becomes
4x2( + 12x - 1x) - 3 = 0
GCF of 4 and 12 = 4
GCF of 4 and -1 = 1
Our first GCF is an integer
Group the terms below:
4x2 and 12x and -1x and -3
This can be written as:
(4x2 + 12x) + (-1x - 3) = 0
Factor out 4x from the first group
Factor out 1 from the second group
4x(x + 3) + 1(-x - 3) = 0
Our common term is (x + 3)
Write this as (4x + 1)(x + 3) = 0
If A x B = 0, then either A = 0 or B = 0
Set each factor to 0 and solve
Factor: (4x + 1)(x + 3) = 0