Calculate the multifactorial 16!3
We have 3 exclamation symbols (!)
Start at 16
Iterate backwards in steps of 3
Stop when we hit 1 or below
For term 1, we start with 16
Subtract -1 x 3 = -3 to get n(n - -3)
(n - -3) → 16 - -3 = 13
Our factorial term is:
16(13)
Subtract -1 x 3 = -3 to get n(n - -3)(n - -3)
(n - -3) → 16 - -3 = 10
Our factorial term is:
16(13)(10)
Subtract -1 x 3 = -3 to get n(n - -3)(n - -3)(n - -3)
(n - -3) → 16 - -3 = 7
Our factorial term is:
16(13)(10)(7)
Subtract -1 x 3 = -3 to get n(n - -3)(n - -3)(n - -3)(n - -3)
(n - -3) → 16 - -3 = 4
Our factorial term is:
16(13)(10)(7)(4)
Subtract -1 x 3 = -3 to get n(n - -3)(n - -3)(n - -3)(n - -3)(n - -3)
(n - -3) → 16 - -3 = 1
Our factorial term is:
16(13)(10)(7)(4)(1)
16!3 = n(n - -3)(n - -3)(n - -3)(n - -3)(n - -3)...
16!3 = 16(13)(10)(7)(4)(1)