Solve, factor, complte the square
find the concavity, vertex, vertex form
axis of symmetry and y-intercept for the quadratic:
x2+x-100>0
a = 1, b = 1, c = -100
x = | -b ± √b2 - 4ac |
2a |
-b = -(1)
-b = -1
Δ = b2 - 4ac:
Δ = 12 - 4 x 1 x -100
Δ = 1 - -400
Δ = 401 <--- Discriminant
Since Δ > 0, we expect two real roots.
√Δ = √(401)
√Δ = 1√401
Numerator 1 = -b + √Δ
Numerator 1 = -1 + 1√401
Numerator 2 = -b - √Δ
Numerator 2 = -1 - 1√401
Denominator = 2 * a
Denominator = 2 * 1
Denominator = 2
Solution 1 = | Numerator 1 |
Denominator |
Solution 1 =;(-1 + 1√401)/2
Solution 2 = | Numerator 2 |
Denominator |
Solution 2 = (-1 - 1√401)/2
(Solution 1, Solution 2) = ((-1 + 1√401)/2, (-1 - 1√401)/2)
(Solution 1, Solution 2) = ((-1 + 1√401)/2, (-1 - 1√401)/2)
The y-intercept is the point where x = 0
Set x = 0 in ƒ(x) = x2 + x - 100>
ƒ(0) = (0)2 + (0) - 100>
ƒ(0) = 0 + 0 - 100
ƒ(0) = -100 ← Y-Intercept
Y-intercept = (0,-100)
(h,k) where y = a(x - h)2 + k
Use the formula rule.
Our equation coefficients are a = 1, b = 1
h = Axis of Symmetry
h = | -b |
2a |
h = | -(1) |
2(1) |
h = | -1 |
2 |
h = -0.5 ← Axis of Symmetry
k = ƒ(h) where h = -0.5
ƒ(h) = (h)2(h)100>
ƒ(-0.5) = (-0.5)2(-0.5)100>
ƒ(-0.5) = 0.25 - 0.5 - 100
ƒ(-0.5) = -100.25
Our vertex (h,k) = (-0.5,-100.25)
The vertex form is: a(x - h)2 + k
Vertex form = (x + 0.5)2 - 100.25
Axis of Symmetry: h = -0.5
vertex (h,k) = (-0.5,-100.25)
Vertex form = (x + 0.5)2 - 100.25
Since our x2 coefficient of 1 is positive
The parabola formed by the quadratic is concave up
concave up
x2 + x - 100> + 100 = 0 + 100
x2 - 0.5x = 100
Add an amount to both sides
x2 + 1x + ? = 100 + ?
Add (½*middle coefficient)2 to each side
Amount to add = | (1 x 1)2 |
(2 x 1)2 |
Amount to add = | (1)2 |
(2)2 |
Amount to add = | 1 |
4 |
Amount to add = 1/4
x2 + 1 + (1/2)2 = 100 + (1/2)2
(x + 1/2)2 = 100 + 1/4
We multiply 100 by 4 ÷ 1 = 4 and 1 by 4 ÷ 4 = 1
Simplified Fraction = | 100 x 4 + 1 x 1 |
4 |
Simplified Fraction = | 400 + 1 |
4 |
Simplified Fraction = | 401 |
4 |
Our fraction can be reduced down:
Using our GCF of 401 and 4 = 401
Reducing top and bottom by 401 we get
1/0.0099750623441397
u2 = (x + 1/2)2
u = +√1/0.0099750623441397
u = -√1/0.0099750623441397
x + 1/2 = +1
x + 1/2 = -1
x + 1/2 - 1/2 = +1/1 - 1/2
We multiply 1 by 2 ÷ 1 = 2 and -1 by 2 ÷ 2 = 1
Simplified Fraction = | 1 x 2 - 1 x 1 |
2 |
Simplified Fraction = | 2 - 1 |
2 |
Simplified Fraction = | 1 |
2 |
Answer 1 = 1/2
x + 1/2 - 1/2 = -1/1 - 1/2
We multiply -1 by 2 ÷ 1 = 2 and -1 by 2 ÷ 2 = 1
Simplified Fraction = | -1 x 2 - 1 x 1 |
2 |
Simplified Fraction = | -2 - 1 |
2 |
Simplified Fraction = | -3 |
2 |
Answer 2 = -3/2
Since a = 1, find all factor pairs of c = -100
These must have a sum = 1
Factor Pairs of -100 | Sum of Factor Pair |
---|---|
1,-100 | 1 - 100 = -99 |
2,-50 | 2 - 50 = -48 |
4,-25 | 4 - 25 = -21 |
5,-20 | 5 - 20 = -15 |
10,-10 | 10 - 10 = 0 |
20,-5 | 20 - 5 = 15 |
25,-4 | 25 - 4 = 21 |
50,-2 | 50 - 2 = 48 |
100,-1 | 100 - 1 = 99 |
Since no factor pairs exist = 1, this quadratic cannot be factored any more
(x + Factor Pair Answer 1)(x + Factor Pair Answer 2)
Factor: (x + 0)(x + 0)