rectangle word problem

A family room measures 15.6 feet long and 18.4 feet wide. What is the area of the room? The room is rectangular. So our area A = lw. Using our rectangle calculator, we get: A = 287.04 square feet

A chalkboard is 3 feet tall and 4 feet long. What is its perimeter A chalkboard is a rectangle. So the perimeter is: 2l + 2w Using our rectangle calculator, we get: P = 14

A rectangular parking lot has a perimeter of 152 yards. If the length of the parking lot is 12 yards greater than the width. What is the width of the parking lot? The perimeter of a rectangle is: 2l + 2w = P. We're given 2 equations: 2l + 2w = 152 l = w + 12 Substitute equation (2) into...

The width of a rectangle is fixed at 4cm. For what lengths will the area be less than 86 cm^2 The Area (A) of a rectangle is given by: A = lw With an area of less than 86 and a width of 4, we have the following inequality: 4l < 86 To solve for l, we type this inequality into our search engine...

A rectangular room is 3 times as long as it is wide, and its perimeter is 56 meters. Find the dimensions of the room. We're given two items: l = 3w P = 56 We know the perimeter of a rectangle is: 2l + 2w = P We plug in the given values l = 3w and P = 56 to get: 2(3w) + 2w = 56 6w + 2w = 56...

The perimeter of a rectangular backyard is 162 feet. It is 52 feet long. How wide is it? We use our rectangle solver to solve for w. We get: w = 29

A rectangular room is 3 times as long as it is wide, and its perimeter is 64 meters. Find the dimension of the room. We're given: l = 3w P = 64 We also know the perimeter of a rectangle is: 2l + 2w = P We plugin l = 3w and P = 64 into the perimeter equation: 2(3w) + 2w = 64 Multiply through...

A framed print measures 80cm by 65cm. The frame is 5cm wide. Find the area of the unframed print. We subtract 5 cm from the length and the width to account for the frame: Unframed Length: 80 - 5 = 75 Unframed Width: 65 - 5 = 60 Area of the unframed rectangle is: A = lw A = 75(60) A = 4,500 sq cm

Allan built an additional room onto his house. The length of the room is 3 times the width. The perimeter of the room is 60 feet. What is the length of the room A room is a rectangle. We know the perimeter of a rectangle is: P = 2l + 2w We're given two equations: l = 3w P = 60 Plug (1) and...

A rectangular room is 4 times as long as it is wide, and its perimeter is 80 meters. Find the dimension of the room The perimeter of a rectangle is P = 2l + 2w. We're given two equations: l = 4w 2l + 2w = 80. <-- Since perimeter is 80 Plug equation (1) into equation (2) for l: 2(4w) + 2w = 80...

A train ticket is 8 centimeters tall and 10 centimeters long. What is its area? The ticket is a rectangle. The area is: A = lw Plugging in our numbers, we get: A = (8)(10) A = 80

A rectangular room is 3 times as long as it is wide, and its perimeter is 56 meters. We're given the following: l = 3w We know the Perimeter (P) of a rectangle is: P = 2l + 2w Substituting l = 3w and P = 56 into this equation, we get: 2(3w) + 2w = 56 Multiplying through, we get: 6w + 2w =...

If the perimeter of a rectangular sign is 44cm and the width is 2cm shorter than half the length, then what are the length and width? The perimeter (P) of a rectangle is: 2l + 2w = P We're given P = 44, so we substitute this into the rectangle perimeter equation: 2l + 2w = 44 We're also given...

A RECTANGLE HAS A PERIMETER OF 196 CENTIMETERS. IF THE LENGTH IS 6 TIMES ITS WIDTH FIND TH DIMENSIONS OF THE RECTANGLE? Whoa... stop screaming with those capital letters! But I digress... The perimeter of a rectangle is: P = 2l + 2w We're given two equations: P = 196 l = 6w Plug these into...

The perimeter of a college basketball court is 102 meters and the length is twice as long as the width. What are the length and width? A basketball court is a rectangle. The perimeter P is: P = 2l + 2w We're also given l = 2w and P = 102. Plug these into the perimeter formula: 2(2w) + 2w = 102...

A rectangular field is to be enclosed with 1120 feet of fencing. If the length of the field is 40 feet longer than the width, then how wide is the field? We're given: l = w + 40 And we know the perimeter of a rectangle is: P = 2l + 2w Substitute (1) into this formula as well as the given...

A yard is 33.21 meters long and 17.6 meters wide. What length of fence must be purchased to enclose the entire yard? The yard is a rectangle. The perimeter of a rectangle is: P = 2l + 2w where l is the length and w is the width. Evaluating, using our rectangle calculator, we get P = 101.62

A 7 by 5 photo was enlarged. The length and width were enlarged 125%. Find the perimeter of the photo. Enlarge length 125%: 7 * 1.25 = 8.75 Enlarge width 125%: 5 * 1.25 = 6.25 Perimeter of the enlarged photo is 2l + 2w, so we have: P = 2(8.75) + 2(6.25) P = 17.5 + 12.5 P = 30

The perimeter of a garden is 70 meters. Find its actual dimensions if its length is 5 meters longer than twice its width. Let w be the width, and l be the length. We have: P = l + w. Since P = 70, we have: l + w = 70 l = 2w + 5 Plug (2) into (1) 2w + 5 + w = 70 Group like terms: 3w + 5 =...

Sheila wants build a rectangular play space for her dog. She has 100 feet of fencing and she wants it to be 5 times as long as it is wide. What dimensions should the play area be? Sheila wants: l =5w 2l + 2w = 100 <-- Perimeter Substitute (1) into (2) 2(5w) + 2w = 100 10w + 2w = 100 12w =...