The sum of three consecutive integers equals 36. What are the three numbers?
Set up an equation where our numbers are n, n + 1, and n + 2
n + (n + 1) + (n + 2) = 36
Group variables and constants together:
(n + n + n) + 1 + 2 = 363n + 3 = 36
Subtract 3 from each side:
3n + 3 - 3 = 36 - 3Cancel the 3 on the left side and we get:
3n = 33Divide each side of the equation by 3 to isolate n:
| 3n | |
| 3 |
| = |
| 33 |
| 3 |
Cancel the 3 on the left side:
| = |
| 33 |
| 3 |
n = 11
Call this n1, so we find our other two numbers
n2 = n1 + 1
n2 = 11 + 1
n2 = 12
n3 = n1 + 2
n3 = 11 + 2
n3 = 13
So we have three consecutive integers (n1, n2, n3) = (11, 12, 13) with a sum 11 + 12 + 13 equal to 36
What is the Answer?
So we have three consecutive integers (n1, n2, n3) = (11, 12, 13) with a sum 11 + 12 + 13 equal to 36
How does the Sum of Three Consecutive Integers Calculator work?
Free Sum of Three Consecutive Integers Calculator - Finds three consecutive integers, if applicable, who have a sum equal to a number.
Sum of 3 consecutive integers
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What 1 formula is used for the Sum of Three Consecutive Integers Calculator?
What 4 concepts are covered in the Sum of Three Consecutive Integers Calculator?
- consecutive integers
- integers that follow each other
n, n + 1 - integer
- a whole number; a number that is not a fraction
...,-5,-4,-3,-2,-1,0,1,2,3,4,5,... - sum of three consecutive integers
- word problem
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