The sum of three consecutive integers equals 36. What are the three numbers?
Set up an equation where our numbers are n, n + 1, and n + 2 n + (n + 1) + (n + 2) = 36
Group variables and constants together:
(n + n + n) + 1 + 2 = 36 3n + 3 = 36
Subtract 3 from each side:
3n + 3 - 3 = 36 - 3
Cancel the 3 on the left side and we get:
3n = 33
Divide each side of the equation by 3 to isolate n:
3n
3
=
33
3
Cancel the 3 on the left side:
3n
3
=
33
3
n = 11
Call this n1, so we find our other two numbers n2 = n1 + 1 n2 = 11 + 1 n2 = 12
n3 = n1 + 2 n3 = 11 + 2 n3 = 13
So we have three consecutive integers (n1, n2, n3) = (11, 12, 13) with a sum 11 + 12 + 13 equal to 36
What is the Answer?
So we have three consecutive integers (n1, n2, n3) = (11, 12, 13) with a sum 11 + 12 + 13 equal to 36
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Free Sum of Three Consecutive Integers Calculator - Finds three consecutive integers, if applicable, who have a sum equal to a number.
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