Find five consecutive integers with a sum of 65

Sum of five consecutive numbers equals
  

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The sum of five consecutive integers equals 65. What are the five numbers?

Set up an equation where our numbers are n, n + 1, n + 2, n + 3, and n + 4
n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 65

Group variables and constants together:

(n + n + n + n + n) + 1 + 2 + 3 + 4 = 65
5n + 10 = 65

Subtract 10 from each side:

5n + 10 - 10 = 65 - 10

Cancel the 10 on the left side and we get:

5n = 55

Divide each side of the equation by 5 to isolate n:

5n
5

=

55

5

Cancel the 5 on the left side:

5n
5

=

55

5

n = 11

Call this n₁, so we find our other two numbers
n₂ = n₁ + 1
n₂ = 11 + 1
n₂ = 12

n₃ = n₁ + 2
n₃ = 11 + 2
n₃ = 13

n₄ = n₁ + 3
n₄ = 11 + 3
n₄ = 14

n₄ = n₁ + 4
n₄ = 11 + 3
n₄ = 15

So we have five consecutive integers (n₁, n₂, n₃, n₄, n₅) = (11, 12, 13, 14, 15)