You entered a number set X of {69,79,54,77,98,100}
From the 6 numbers you entered, we want to calculate the mean, variance, standard deviation, standard error of the mean, skewness, average deviation (mean absolute deviation), median, mode, range, Pearsons Skewness Coefficient of that number set, entropy, mid-range
54, 69, 77, 79, 98, 100
Rank Ascending
54 is the 1st lowest/smallest number
69 is the 2nd lowest/smallest number
77 is the 3rd lowest/smallest number
79 is the 4th lowest/smallest number
98 is the 5th lowest/smallest number
100 is the 6th lowest/smallest number
100, 98, 79, 77, 69, 54
Rank Descending
100 is the 1st highest/largest number
98 is the 2nd highest/largest number
79 is the 3rd highest/largest number
77 is the 4th highest/largest number
69 is the 5th highest/largest number
54 is the 6th highest/largest number
Sort our number set in ascending order
and assign a ranking to each number:
Number Set Value | 54 | 69 | 77 | 79 | 98 | 100 |
Rank | 1 | 2 | 3 | 4 | 5 | 6 |
Since we have 6 numbers in our original number set,
we assign ranks from lowest to highest (1 to 6)
Our original number set in unsorted order was 54,69,77,79,98,100
Our respective ranked data set is 1,2,3,4,5,6
Root Mean Square = | √A |
√N |
where A = x12 + x22 + x32 + x42 + x52 + x62 and N = 6 number set items
A = 542 + 692 + 772 + 792 + 982 + 1002
A = 2916 + 4761 + 5929 + 6241 + 9604 + 10000
A = 39451
RMS = | √39451 |
√6 |
RMS = | 198.62275801126 |
2.4494897427832 |
RMS = 81.087401405315
Central tendency contains:
Mean, median, mode, harmonic mean,
geometric mean, mid-range, weighted-average:
μ = | Sum of your number Set |
Total Numbers Entered |
μ = | ΣXi |
n |
μ = | 54 + 69 + 77 + 79 + 98 + 100 |
6 |
μ = | 477 |
6 |
μ = 79.5
Since our number set contains 6 elements which is an even number,
our median number is determined as follows
Number Set = (n1,n2,n3,n4,n5,n6)
Median Number 1 = ½(n)
Median Number 1 = ½(6)
Median Number 1 = Number Set Entry 3
Median Number 2 = Median Number 1 + 1
Median Number 2 = Number Set Entry 3 + 1
Median Number 2 = Number Set Entry 4
Median = ½(n3 + n4)
Our median is the average of entry 3 and entry 4 of our number set highlighted in red:
(54,69,77,79,98,100)
Median = ½(77 + 79)
Median = ½(156)
Median = 78
The highest frequency of occurence in our number set is 1 times
by the following numbers in green:
()
Since the maximum frequency of any number is 1, no mode exists.
Mode = N/A
Harmonic Mean = | N |
1/x1 + 1/x2 + 1/x3 + 1/x4 + 1/x5 + 1/x6 |
With N = 6 and each xi a member of the number set you entered, we have:
Harmonic Mean = | 6 |
1/54 + 1/69 + 1/77 + 1/79 + 1/98 + 1/100 |
Harmonic Mean = | 6 |
0.018518518518519 + 0.014492753623188 + 0.012987012987013 + 0.012658227848101 + 0.010204081632653 + 0.01 |
Harmonic Mean = | 6 |
0.078860594609474 |
Harmonic Mean = 76.083626172395
Geometric Mean = (x1 * x2 * x3 * x4 * x5 * x6)1/N
Geometric Mean = (54 * 69 * 77 * 79 * 98 * 100)1/6
Geometric Mean = 2221195284000.16666666666667
Geometric Mean = 77.821176190776
Mid-Range = | Maximum Value in Number Set + Minimum Value in Number Set |
2 |
Mid-Range = | 100 + 54 |
2 |
Mid-Range = | 154 |
2 |
Mid-Range = 77
Take the first digit of each value in our number set
Use this as our stem value
Use the remaining digits for our leaf portion
{100,98,79,77,69,54}
Stem | Leaf |
---|---|
1 | 00 |
9 | 8 |
7 | 7,9 |
6 | 9 |
5 | 4 |
Mean, Variance, Standard Deviation, Median, Mode
μ = | Sum of your number Set |
Total Numbers Entered |
μ = | ΣXi |
n |
μ = | 54 + 69 + 77 + 79 + 98 + 100 |
6 |
μ = | 477 |
6 |
μ = 79.5
Let's evaluate the square difference from the mean of each term (Xi - μ)2:
(X1 - μ)2 = (54 - 79.5)2 = -25.52 = 650.25
(X2 - μ)2 = (69 - 79.5)2 = -10.52 = 110.25
(X3 - μ)2 = (77 - 79.5)2 = -2.52 = 6.25
(X4 - μ)2 = (79 - 79.5)2 = -0.52 = 0.25
(X5 - μ)2 = (98 - 79.5)2 = 18.52 = 342.25
(X6 - μ)2 = (100 - 79.5)2 = 20.52 = 420.25
ΣE(Xi - μ)2 = 650.25 + 110.25 + 6.25 + 0.25 + 342.25 + 420.25
ΣE(Xi - μ)2 = 1529.5
Population | Sample | ||||||||
---|---|---|---|---|---|---|---|---|---|
|
|
|
| ||||||
Variance: σp2 = 254.91666666667 | Variance: σs2 = 305.9 | ||||||||
Standard Deviation: σp = √σp2 = √254.91666666667 | Standard Deviation: σs = √σs2 = √305.9 | ||||||||
Standard Deviation: σp = 15.9661 | Standard Deviation: σs = 17.49 |
Population | Sample | ||||||||
---|---|---|---|---|---|---|---|---|---|
|
|
|
|
|
| ||||
SEM = 6.5181 | SEM = 7.1403 |
Skewness = | E(Xi - μ)3 |
(n - 1)σ3 |
Let's evaluate the square difference from the mean of each term (Xi - μ)3:
(X1 - μ)3 = (54 - 79.5)3 = -25.53 = -16581.375
(X2 - μ)3 = (69 - 79.5)3 = -10.53 = -1157.625
(X3 - μ)3 = (77 - 79.5)3 = -2.53 = -15.625
(X4 - μ)3 = (79 - 79.5)3 = -0.53 = -0.125
(X5 - μ)3 = (98 - 79.5)3 = 18.53 = 6331.625
(X6 - μ)3 = (100 - 79.5)3 = 20.53 = 8615.125
ΣE(Xi - μ)3 = -16581.375 + -1157.625 + -15.625 + -0.125 + 6331.625 + 8615.125
ΣE(Xi - μ)3 = -2808
Skewness = | E(Xi - μ)3 |
(n - 1)σ3 |
Skewness = | -2808 |
(6 - 1)15.96613 |
Skewness = | -2808 |
(5)4070.0199231218 |
Skewness = | -2808 |
20350.099615609 |
Skewness = -0.13798458253473
AD = | Σ|Xi - μ| |
n |
Evaluate the absolute value of the difference from the mean
|Xi - μ|:
|X1 - μ| = |54 - 79.5| = |-25.5| = 25.5
|X2 - μ| = |69 - 79.5| = |-10.5| = 10.5
|X3 - μ| = |77 - 79.5| = |-2.5| = 2.5
|X4 - μ| = |79 - 79.5| = |-0.5| = 0.5
|X5 - μ| = |98 - 79.5| = |18.5| = 18.5
|X6 - μ| = |100 - 79.5| = |20.5| = 20.5
Σ|Xi - μ| = 25.5 + 10.5 + 2.5 + 0.5 + 18.5 + 20.5
Σ|Xi - μ| = 78
Calculate average deviation (mean absolute deviation)
AD = | Σ|Xi - μ| |
n |
AD = | 78 |
6 |
Average Deviation = 13
Since our number set contains 6 elements which is an even number,
our median number is determined as follows
Number Set = (n1,n2,n3,n4,n5,n6)
Median Number 1 = ½(n)
Median Number 1 = ½(6)
Median Number 1 = Number Set Entry 3
Median Number 2 = Median Number 1 + 1
Median Number 2 = Number Set Entry 3 + 1
Median Number 2 = Number Set Entry 4
Median = ½(n3 + n4)
Our median is the average of entry 3 and entry 4 of our number set highlighted in red:
(54,69,77,79,98,100)
Median = ½(77 + 79)
Median = ½(156)
Median = 78
The highest frequency of occurence in our number set is 1 times
by the following numbers in green:
()
Since the maximum frequency of any number is 1, no mode exists.
Mode = N/A
Range = Largest Number in the Number Set - Smallest Number in the Number Set
Range = 100 - 54
Range = 46
PSC1 = | μ - Mode |
σ |
PSC1 = | 3(79.5 - N/A) |
15.9661 |
Since no mode exists, we do not have a Pearsons Skewness Coefficient 1
PSC2 = | μ - Median |
σ |
PSC1 = | 3(79.5 - 78) |
15.9661 |
PSC2 = | 3 x 1.5 |
15.9661 |
PSC2 = | 4.5 |
15.9661 |
PSC2 = 0.2818
Entropy = Ln(n)
Entropy = Ln(6)
Entropy = 1.7917594692281
Mid-Range = | Smallest Number in the Set + Largest Number in the Set |
2 |
Mid-Range = | 100 + 54 |
2 |
Mid-Range = | 154 |
2 |
Mid-Range = 77
We need to sort our number set from lowest to highest shown below:
{54,69,77,79,98,100}
V = | y(n + 1) |
100 |
V = | 75(6 + 1) |
100 |
V = | 75(7) |
100 |
V = | 525 |
100 |
V = 5 ← Rounded down to the nearest integer
Upper quartile (UQ) point = Point # 5 in the dataset which is 98
54,69,77,79,98,100V = | y(n + 1) |
100 |
V = | 25(6 + 1) |
100 |
V = | 25(7) |
100 |
V = | 175 |
100 |
V = 2 ← Rounded up to the nearest integer
Lower quartile (LQ) point = Point # 2 in the dataset which is 69
54,69,77,79,98,100
IQR = UQ - LQ
IQR = 98 - 69
IQR = 29
Lower Inner Fence (LIF) = LQ - 1.5 x IQR
Lower Inner Fence (LIF) = 69 - 1.5 x 29
Lower Inner Fence (LIF) = 69 - 43.5
Lower Inner Fence (LIF) = 25.5
Upper Inner Fence (UIF) = UQ + 1.5 x IQR
Upper Inner Fence (UIF) = 98 + 1.5 x 29
Upper Inner Fence (UIF) = 98 + 43.5
Upper Inner Fence (UIF) = 141.5
Lower Outer Fence (LOF) = LQ - 3 x IQR
Lower Outer Fence (LOF) = 69 - 3 x 29
Lower Outer Fence (LOF) = 69 - 87
Lower Outer Fence (LOF) = -18
Upper Outer Fence (UOF) = UQ + 3 x IQR
Upper Outer Fence (UOF) = 98 + 3 x 29
Upper Outer Fence (UOF) = 98 + 87
Upper Outer Fence (UOF) = 185
Suspect Outliers are values between the inner and outer fences
We wish to mark all values in our dataset (v) in red below such that -18 < v < 25.5 and 141.5 < v < 185
54,69,77,79,98,100
Highly Suspect Outliers are values outside the outer fences
We wish to mark all values in our dataset (v) in red below such that v < -18 or v > 185
54,69,77,79,98,100
54, 69, 77, 79, 98, 100
Multiply each value by each probability amount
We do this by multiplying each Xi x pi to get a weighted score Y
Weighted Average = | X1p1 + X2p2 + X3p3 + X4p4 + X5p5 + X6p6 |
n |
Weighted Average = | 54 x + 69 x + 77 x + 79 x + 98 x + 100 x |
6 |
Weighted Average = | 0 + 0 + 0 + 0 + 0 + 0 |
6 |
Weighted Average = | 0 |
6 |
Weighted Average = 0
Show the freqency distribution table for this number set
54, 69, 77, 79, 98, 100
We need to choose the smallest integer k such that 2k ≥ n where n = 6
For k = 1, we have 21 = 2
For k = 2, we have 22 = 4
For k = 3, we have 23 = 8 ← Use this since it is greater than our n value of 6
Therefore, we use 3 intervals
Our maximum value in our number set of 100 - 54 = 46
Each interval size is the difference of the maximum and minimum value divided by the number of intervals
Interval Size = | 46 |
3 |
Add 1 to this giving us 15 + 1 = 16
Class Limits | Class Boundaries | FD | CFD | RFD | CRFD |
---|---|---|---|---|---|
54 - 70 | 53.5 - 70.5 | 2 | 2 | 2/6 = 33.33% | 2/6 = 33.33% |
70 - 86 | 69.5 - 86.5 | 2 | 2 + 2 = 4 | 2/6 = 33.33% | 4/6 = 66.67% |
86 - 102 | 85.5 - 102.5 | 2 | 2 + 2 + 2 = 6 | 2/6 = 33.33% | 6/6 = 100% |
6 | 100% |
Go through our 6 numbers
Determine the ratio of each number to the next one
54:69 → 0.7826
69:77 → 0.8961
77:79 → 0.9747
79:98 → 0.8061
98:100 → 0.98
Successive Ratio = 54:69,69:77,77:79,79:98,98:100 or 0.7826,0.8961,0.9747,0.8061,0.98