Use the substitution method to solve:
x + 2y = 22
2x + y = 28
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for x:
2x + y = 28
Subtract y from both sides to isolate x:
2x + y - y = 28 - y
2x = 28 - y
Plug Revised Equation 2 value into x:
1(x) + 2y = 22
1 * (28 - y) + 2y = 22
((28 - 1y)/2) + 2y = 22
Multiply equation 1 through by 2
2 * (((28 - 1y)/2) + 2y = 22)
2 * (((28 - 1y)/2) + 2y = 22)
28 - 1y + 4y = 44
Group like terms:
-1y + 4y = 44 - 28
3y = 16
Divide each side by 3
| 3y | |
| 3 |
| = |
| 16 |
| 3 |
| y = | 16 |
| 3 |
y = 5.3333333333333
Plug this answer into Equation 1
1x + 2(5.3333333333333) = 22
1x + 10.666666666667 = 22
1x = 22 - 10.666666666667
1x = 11.333333333333
Divide each side by 1
| 1x | |
| 1 |
| = |
| 11.333333333333 |
| 1 |
| x = | 11.333333333333 |
| 1 |
x = 11.333333333333
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