2 tens
Ten-Groups = 10 + 10
Ten-Groups = 20
3 ones
23 = 0 Hundreds + 20 Tens + 3 ones
23 = 0 + 20 + 3
Show numerical properties of 23
23
twenty three
Decompose 23
Each digit in the whole number represents a power of 10:
Take the whole number portion on the left side of the decimal
Expanded Notation of 23 = (2 x 101) + (3 x 100)
Expanded Notation of 23 = (2 x 10) + (3 x 1)
23 = 20 + 3
23 = 23 <---- Correct!
Make blocks of 5
1 tally mark = |
2 tally marks = ||
3 tally marks = |||
4 tally marks = ||||
5 tally marks = | | | |
5 = | | | |
10 = | | | |
15 = | | | |
20 = | | | |
23 = | | |
| | | | | | | | | | | | | | | | | | |
Define an ordinal number
A position in a list
23rd
Calculate the digit sum of 23
Calculate the reduced digit sum of 23
Digit Sum → 2 + 3 = 5
Since our digit sum ≤ 9:
we have our reduced digit sum
Digit Sum → 2 + 3 = 5
Calculate the digit product of 23
Digit Product = Value when you multiply
all the digits of a number together.
We multiply the 2 digits of 23 together
Digit product of 23 = 2 * 3
Digit product of 23 = 6
Opposite of 23 = -(23)
Opposite of = -23
Place value describes each digit
2 is our tens digit
This means we have 2 sets of tens
3 is our ones digit
This means we have 3 sets of ones
2 is our tens digit
3 is our ones digit
When ey = x and e = 2.718281828459
We have Ln(x) = loge(x) = y
Ln(23) = loge(23) = 3.1354942159291
Is 23 divisible by:
2,3,4,5,6,7,8,9,10,11
Last digit ends in 0,2,4,6,8
The last digit of 23 is 3
Since 3 is not equal to 0,2,4,6,8:
then 23 is not divisible by 2
Sum of the digits is divisible by 3
The sum of the digits for 23 is 2 + 3 = 5
Since 5 is not divisible by 3:
Then 23 is not divisible by 3
Take the last two digits
Are they divisible by 4?
The last 2 digits of 23 are 23
Since 23 is not divisible by 4:
Then 23 is not divisible by 4
Number ends with a 0 or 5
The last digit of 23 is 3
Since 3 is not equal to 0 or 5:
Then 23 is not divisible by 5
Divisible by both 2 and 3
Since 23 is not divisible by 2 and 3:
Then 23 is not divisible by 6
Multiply each respective digit by 1,3,2,6,4,5
Work backwards
Repeat as necessary
3(1) + 2(3) = 10
Since 10 is not divisible by 7:
Then 23 is not divisible by 7
Take the last three digits
Are they divisible by 8
The last 2 digits of 23 are 23
Since 23 is not divisible by 8:
Then 23 is not divisible by 8
Sum of digits divisible by 9
The sum of the digits for 23 is 2 + 3 = 5
Since 5 is not divisible by 9:
Then 23 is not divisible by 9
Ends with a 0
The last digit of 23 is 3
Since 3 is not equal to 0:
Then 23 is not divisible by 10
Σ odd digits - Σ even digits = 0
or 23 is a multiple of 11
23
2
Odd Sum = 2
23
3
Even Sum = 3
Δ = Odd Sum - Even Sum
Δ = 2 - 3
Δ = -1
Because Δ / 11 = 2.0909090909091:
Then 23 is NOT divisible by 11