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Convert 227 from decimal to binary

(base 2) notation:

Power Test

Raise our base of 2 to a power

Start at 0 and increasing by 1 until it is >= 227

2⁰ = 1

2¹ = 2

2² = 4

2³ = 8

2⁴ = 16

2⁵ = 32

2⁶ = 64

2⁷ = 128

2⁸ = 256 <--- Stop: This is greater than 227

Since 256 is greater than 227, we use 1 power less as our starting point which equals 7

Build binary notation

Work backwards from a power of 7

We start with a total sum of 0:

2⁷ = 128

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 128 = 128

Add our new value to our running total, we get:
0 + 128 = 128

This is <= 227, so we assign our outside coefficient of 1 for this digit.

Our new sum becomes 128

Our binary notation is now equal to 1

2⁶ = 64

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 64 = 64

Add our new value to our running total, we get:
128 + 64 = 192

This is <= 227, so we assign our outside coefficient of 1 for this digit.

Our new sum becomes 192

Our binary notation is now equal to 11

2⁵ = 32

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 32 = 32

Add our new value to our running total, we get:
192 + 32 = 224

This is <= 227, so we assign our outside coefficient of 1 for this digit.

Our new sum becomes 224

Our binary notation is now equal to 111

2⁴ = 16

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 16 = 16

Add our new value to our running total, we get:
224 + 16 = 240

This is > 227, so we assign a 0 for this digit.

Our total sum remains the same at 224

Our binary notation is now equal to 1110

2³ = 8

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 8 = 8

Add our new value to our running total, we get:
224 + 8 = 232

This is > 227, so we assign a 0 for this digit.

Our total sum remains the same at 224

Our binary notation is now equal to 11100

2² = 4

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 4 = 4

Add our new value to our running total, we get:
224 + 4 = 228

This is > 227, so we assign a 0 for this digit.

Our total sum remains the same at 224

Our binary notation is now equal to 111000

2¹ = 2

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 2 = 2

Add our new value to our running total, we get:
224 + 2 = 226

This is <= 227, so we assign our outside coefficient of 1 for this digit.

Our new sum becomes 226

Our binary notation is now equal to 1110001

2⁰ = 1

The highest coefficient less than 1 we can multiply this by to stay under 227 is 1

Multiplying this coefficient by our original value, we get: 1 * 1 = 1

Add our new value to our running total, we get:
226 + 1 = 227

This = 227, so we assign our outside coefficient of 1 for this digit.

Our new sum becomes 227

Our binary notation is now equal to 11100011

Final Answer