Bob fenced in his backyard. The perimeter of the yard is 22 feet, and the length of his yard is 5 fe | MathCelebrity Forum

Bob fenced in his backyard. The perimeter of the yard is 22 feet, and the length of his yard is 5 fe

math_celebrity

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Bob fenced in his backyard. The perimeter of the yard is 22 feet, and the length of his yard is 5 feet. Use the perimeter formula to find the width of the rectangular yard in inches: P = 2L + 2W.

Plugging our numbers in for P = 22 and L = 5, we get:
22 = 2(5) + 2W
22 = 10 + 2w

Rewritten, we have:
10 + 2w = 22

Plug this equation into the search engine, we get:
w = 6
 
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