2 times as many dimes as quarters and they have a combined value of 180 cents, how many of each coin does he have?
Let d be the number of dimes. Let q be the number of quarters. We're given two equations:
0.1(2q) + 0.25q = 180
0.2q + 0.25q = 180
Typing this equation into the search engine, we get:
q = 400
Now substitute q = 400 into equation 1:
d = 2(400)
d = 800
Let d be the number of dimes. Let q be the number of quarters. We're given two equations:
- d = 2q
- 0.1d + 0.25q = 180
0.1(2q) + 0.25q = 180
0.2q + 0.25q = 180
Typing this equation into the search engine, we get:
q = 400
Now substitute q = 400 into equation 1:
d = 2(400)
d = 800