segment

If FG = x + 1, GH = 2x, and FH = 4, what is FG? FG + GH = FH due to segment addition x + 1 + 2x = 4 Typing this equation into our math engine, we get: x = 1 FG = 1 + 1 FG = 2

pq = 7x, qr = x + 1, and pr = 9, what is qr PQ + QR = PR 7x + x + 1 = 9 Using our equation solver, we get: x = 1 Plug in x = 1 to QR: 1 + 1 = 2

KL=4, and JK=9 Find JL Using segment addition, we know that: JL = JK + KL JL = 9 + 4 JL = 13

If EF = 9x - 17, FG = 17x - 14, and EG = 20x + 17, what is FG? By segment addition, we know that: EF + FG = EG Substituting in our values for the 3 segments, we get: 9x - 17 + 17x - 14 = 20x + 17 Group like terms and simplify: (9 + 17)x + (-17 - 14) = 20x - 17 26x - 31 = 20x - 17 Solve for x...

If FG = 9, GH = 4x, and FH = 7x, what is GH? By segment addition, we have: FG + GH = FH Substituting in the values given, we have: 9 + 4x = 7x To solve this equation for x, we type it in our math engine and we get: x = 3 The question asks for GH, so with x = 3, we have: GH = 4(3) GH = 12

If Ef = 3x,Fg = 2x,and EG = 5 By segment addition, we have: EF + FG = EG 3x + 2x = 5 To solve for x, we type this equation into our math engine and we get: x = 1 So EF = 3(1) = 3 FG = 2(1) = 2

C is the midpoint of BD then BC congruent CD True using this proof

If EF = 7x , FG = 3x , and EG = 10 , what is EF? By segment addition: EF + FG = EG 7x + 3x = 10 To solve this equation for x, we type it in our search engine and we get: x = 1 Evaluating EF = 7x with x = 1, we get: EF = 7 * 1 EF = 7

If FG=11, GH=x-2, and FH=3x-11, what is FH By segment addition, we have: FG + GH = FH 11 + x - 2 = 3x - 11 To solve this equation for x, we type it in or math engine and we get: x = 10 FH = 3x - 11. So we substitute x = 10 into this: FH = 3(10) - 11 FH = 30 - 11 FH = 19

Points A, B, and C are collinear. Point B is between A and C. Find AB if AC=15 and BC=7. Collinear means on the same line. By segment subtraction, we have: AB = AC - BC AB = 15 - 7 AB = 8

PQ=3.7 and PR=14.1 what is QR QR = PR - PQ by segment addition QR = 14.1 - 3.7 QR = 10.4

X bisects WY. XY=32 and WY=2x. Find x and WY\ Bisects means split into two equal parts. So we have: XY = 32 WX = XY If XY = 32, then: WY = 2 * 32 = 64 So x = 32

If RS = 3.3 and RT = 5.9, what is ST? ST = RT - RS ST = 5.9 - 3.3 ST = 2.6

Q is a point on segment PR. If PQ = 2.7 and PR = 6.1, what is QR? From segment addition, we know that: PQ + QR = PR Plugging our given numbers in, we get: 2.7 + QR = 6.1 Subtract 2.7 from each side, and we get: 2.7 - 2.7 + QR = 6.1 - 2.7 Cancelling the 2.7 on the left side, we get: QR = 3.4

If QR = 16, RS = 4x − 17, and QS = x + 20, what is RS? From the segment addition rule, we have: QR + RS = QS Plugging our values in for each of these segments, we get: 16 + 4x - 17 = x + 20 To solve this equation for x, we type it in our search engine and we get: x = 7 Take x = 7 and...

Given: BC = EF AC = EG AB = 10 BC = 3 Prove FG = 10 AC = AB + BC (Segment Addition Postulate) AB = 10, BC = 3 (Given) AC = 10 + 3 (Substitution Property of Equality) AC = 13 (Simplify) AC = EG, BC = EF (Given) EG = 13, EF = 3 (Segment Equivalence) EG = EF + FG (Segment Addition Postulate)...