Find 2 consecutive integers with
a sum of 111
Setup relational equation
We need to find 2 integers, n and n + 1, who have a sum = 111
n + (n + 1) = 111
Grouping like terms, we get 2n + 1 = 111
Subtract 1 from each side:
2n + 1 - 1 = 111 - 1Cancel the ±1 from each side and simplify:
2n + 1 - 1 = 111 - 1
2n = 110
Divide each side by 2:
| 2n |
| = |
| 110 |
| 2 |
Cancel the 2's on the left side of the equation and simplify:
| = |
| 110 |
| 2 |
First Answer:
n = 55
Determine the 2nd Integer:
Now, since we found our first integer, our 2nd integer is just one greater:
(n + 1) = 55 + 1
Second Answer:
(n + 1) = 56
Final Answers:
n = 55
(n + 1) = 56
(n + 1) = 56
What is the Answer?
n = 55
(n + 1) = 56
(n + 1) = 56
How does the Consecutive Integer Word Problems Calculator work?
Free Consecutive Integer Word Problems Calculator - Calculates the word problem for what two consecutive integers, if summed up or multiplied together, equal a number entered.
This calculator has 1 input.
This calculator has 1 input.
What 2 formulas are used for the Consecutive Integer Word Problems Calculator?
n + (n + 1) = Sum of Consecutive Integers
n(n + 1) = Product of Consecutive Integers
n(n + 1) = Product of Consecutive Integers
What 6 concepts are covered in the Consecutive Integer Word Problems Calculator?
- consecutive integer word problems
- consecutive integers
- integers that follow each other
n, n + 1 - integer
- a whole number; a number that is not a fraction
...,-5,-4,-3,-2,-1,0,1,2,3,4,5,... - product
- The answer when two or more values are multiplied together
- sum
- the total amount resulting from the addition of two or more numbers, amounts, or items
- word problem
- Math problems involving a lengthy description and not just math symbols
