There are 2 consecutive integers. Twice the first increased by the second yields 16. What are the numbers?
Let x be the first integer. y = x + 1 is the next integer. We have the following givens:
2x + (x + 1) = 16
Combine x terms
3x + 1 = 16
Subtract 1 from each side
3x = 15
Divide each side by 3
x = 5
So the other integer is 5 + 1 = 6
Let x be the first integer. y = x + 1 is the next integer. We have the following givens:
- 2x + y = 16
- y = x + 1
2x + (x + 1) = 16
Combine x terms
3x + 1 = 16
Subtract 1 from each side
3x = 15
Divide each side by 3
x = 5
So the other integer is 5 + 1 = 6