The perimeter of a rectangular field is 220 yd. the length is 30 yd longer than the width. Find the dimensions
We are given the following equations:
2(w + 30) + 2w = 220
2w + 60 + 2w = 220
Combine like terms:
4w + 60 = 220
Plug 4w + 60 = 220 into the search engine, and we get w = 40.
Now plug w = 40 into equation (2)
l = 40 + 30
l = 70
We are given the following equations:
- 220 = 2l + 2w
- l = w + 30
2(w + 30) + 2w = 220
2w + 60 + 2w = 220
Combine like terms:
4w + 60 = 220
Plug 4w + 60 = 220 into the search engine, and we get w = 40.
Now plug w = 40 into equation (2)
l = 40 + 30
l = 70