If tanx = 3/4 ,what is cosx?
tan(x) = sin(x)/cos(x), so we have:
sin(x)/cos(x) = 3/4
cross multiply:
4sin(x) = 3cos(x)
Divide each side by 3 to isolate cos(x):
cos(x) = 4sin(x)/3
tan(x) = sin(x)/cos(x), so we have:
sin(x)/cos(x) = 3/4
cross multiply:
4sin(x) = 3cos(x)
Divide each side by 3 to isolate cos(x):
cos(x) = 4sin(x)/3