A RECTANGLE HAS A PERIMETER OF 196 CENTIMETERS. IF THE LENGTH IS 6 TIMES ITS WIDTH FIND TH DIMENSIONS OF THE RECTANGLE?
Whoa... stop screaming with those capital letters! But I digress...
The perimeter of a rectangle is:
P = 2l + 2w
We're given two equations:
2(6w) + 2w = 196
12w + 2w = 196
Plugging this equation into our search engine, we get:
w = 14
Now we put w = 14 into equation (2) above:
l = 6(14)
l = 84
So our length (l), width (w) of the rectangle is (l, w) = (84, 14)
Let's check our work by plugging this into the perimeter formula:
2(84) + 2(14) ? 196
168 + 28 ? 196
196 = 196 <-- checks out
Whoa... stop screaming with those capital letters! But I digress...
The perimeter of a rectangle is:
P = 2l + 2w
We're given two equations:
- P = 196
- l = 6w
2(6w) + 2w = 196
12w + 2w = 196
Plugging this equation into our search engine, we get:
w = 14
Now we put w = 14 into equation (2) above:
l = 6(14)
l = 84
So our length (l), width (w) of the rectangle is (l, w) = (84, 14)
Let's check our work by plugging this into the perimeter formula:
2(84) + 2(14) ? 196
168 + 28 ? 196
196 = 196 <-- checks out