Solve the following equation
4c-8=10c-80
Solve for c
4c - 8 = 10c - 80
Group our variables 4c and 10c
subtract 10c from both sides
4c - 8 - 10c = 10c - 80 - 10c
-6c - 8 = -80
4c | |
4 |
= |
-8 |
4 |
Group our constants -8 and -80.
add 8 to both sides
-6c - 8 + 8 = -80 + 8
-6c = -72
-6c | |
-6 |
= |
-72 |
-6 |
c = 12